math. We give interactive lesions in Math, worksheets and homework help and is designed in such a way that you can master each an every topic. So what are you waiting for? Avail help as early as possible and master the different topics in maths

Following are few topics on which live tutors are available 24 x 7.You can make use of tutors online and avail the maximum benifit from them

Arithmetic Operations

Exponents

Patterns

Scientific Notation

Algebra

You can avail the oppurtunity of this free maths tutoring online for kids without having much time dealt with the books.

You can avail the oppurtunity of this free maths tutoring online for kids without having much time dealt with the books.

Following are the sample problems solved by our tutors.

Following are the sample problems solved by our tutors.

Example 1: -

A die is thrown. Find the probability of getting

(i) an even number (ii) a number 5 (iii) getting a number less than 4

Solution: -

When a die is thrown the possible outcomes are 1, 2, 3, 4, 5, 6.

Total number of outcomes=6

(i) 2,4,6 are the even numbers.

So number of outcomes favorable to getting an even numbers is 3.

P(getting an even number) = 3/6 = 1/2

(ii) There is only one 5 in the possible outcomes So number of outcomes favorable to getting a 5 is 1.

P(getting a 5) = 1/6

(iii) 1,2,3 are the even numbers. So number of outcomes favorable to getting a number less than 4 is 3.

P(getting a number less than 4) = 3/6 = 1/2

Example 2: -

Find the area of the circle with radius 3 cm

Solution: -

Given radius, r = 3 cm

We know that formula for Area of a circle, A = πr2

Where A is the Area and r is the radius

Here we are going to solve for A

Substituting, A = πr2 = π32 = 9π square centimeter

Therefore area of the circle = 9π square centimeter.

Example 3: -

There are 4 Men and 3 women. 3 people are drawn at

random. What is the probability that

there is at least one women?

Solution: -

Let A denote the event that no women is selected. Getting at least one woman is a complement of no women.

Required probability = P(Ac) = 1 - P(A)

=1 - P(no woman)

=1 - [4C3/7C3]

=1 - (4/35)

= 31/35

P(at least one women) = 31/35

Example 4: -

Find the range of the following data:

x: 2 3 4 7 9

f: 5 7 12 8 6

Solution: -

Highest value in the series = 9

Lowest value in the series = 2

Range = Highest Value – Lowest Value = 9 - 2 = 7

Therefore Range = 7