Free Online tutoring for math is a wonderful way to get help in math and master the topics in math. Our tutors are available 24 x 7 to help you in a simple, clear and understanding method. We can assure that you can see dramatic improvements in your grades. Apart from learning topics, we offer help on assignments and home work problems in math. So what are you waiting for? Avail help as early as possible and master the different topics in math.
Free math tutoring topics
We offer help in almost all topics in math. A few are mentioned below.
- Pre Algebra
- Number Sense
Choose any topic and learn in detail. You can also get work sheets to work out related to each topic.
Free Online Tutoring for Math
In Free online tutoring for math we provide you an opportunity to learn the techniques easily without going into books with a good explanation.
Following are few examples of solved problems.Example 1: -
If the letters of the word " FATHER" are arranged alphabetically as in a dictionary, show that it will occur as the 261 word.Solution: -
There are six letters in the word "FATHER". Since the words are arranged alphabetically, first comes the words starting with A. Then starting with E and then comes the words starting with F. To find the number of words beginning with A, keep A fixed at the first letter and arrange the remaining 5 letters. This can be done in 5! = 120 ways. Similarly the number of words starting with E is 120. Therefore the total number of words beginning with A and E is 240. Now the words begin with F. To find the words beginning with FA, arrange the remaining 4 letters which can be done in 4! = 24 ways. The 241th word is" FAEHRT" and 240+24 = 264 th word is "FATRHE". THE 263RD WORD IS :fatreh" and the 262nd word is "FATHRE". Therefore, the 261th word is "FATHER".
Example 2: -
If the roots of the equation x2
- 2x + 7 = 0 are α and β, find the equation whose roots are α2
+ β and β2
+ αSolution: -
Since α and β are the roots of the equation x2
- 2x + 7 = 0, α + β = 2 and αβ = 7.
Now sum of the roots α2
+ β + β2
+ α = α2
+ α + β
=(α + β)2
- 2αβ + α + β
- 2 x 7+ 2
= 4 -14 + 2 = -8
Product of the roots = (α2
+ β)( β2
+ α) = α2
+ (α + β)3
- 3αβ(α + β) + αβ
- 3 x 7 x 2 + 7
= 49 + 8 - 42 + 7
Therefore the equation whose roots are α2
+ β and β2
+ α is
- (sum of the roots)x + product of the roots = 0
That is x2 + 8x + 22 = 0
Example 3: -
The sum of three numbers in Arithmetic Progression is 42 and their product is 2618. Find the numbers.Solution: -
Let the numbers be a - d, a, a + d
Given that the sum of the number is 42.
That is a - d + a + a + d = 42
3a = 42
That is a = 42/3 =14.
Also given product of the numbers is 2618
That is (a - d) a(a + d) = 2618
) = 2618
) = 2618
Dividing both sides by 14, we get
subtracting 142 from both sides, we get
That is d = ± 3When d = 3 and a = 14, the numbers are 11, 14, 17.
When d = -3 and a = 14, the numbers are 17, 14, 11.